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The length of second's pendulum is incre...

The length of second's pendulum is increased by 21 %, then time period will increase by

A

0.015

B

0.21

C

0.055

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
D
`(T_(2))/(T_(1))=sqrt((1.21l)/(l))=1.10`
`therefore (T_(2)-T_(1))/(T_(1))=0.10 therefore (T_(2)-T_(1))/(T)%=10%`
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