Two pendulums have time period T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

Options

A. `(pi)/(4)`
B. `(pi)/(2)`
C. `(3pi)/(3)`
D. `(pi)/(6)`

Answer

B

Explanation

A bigger pendulum of time period `(5T//4)`. A smaller pendulum will complete `(5//4)` vibration. It means the smaller pendulum will be leading the bigger pendulum by a time of `(T//4)` s. The phase for `(T//4)` s is `(pi//2)`