A simple pendulum is moving simple harmonically with a period of 6 s between two extreme positions B and C about a point O. If the distance between B and C is 10 cm, then the time taken by the pendulum to move from position C to position D exactly midway between O and C will be

Options

A. 0.5 s
B. 1.0 s
C. 1.5 s
D. 3 s

Answer

B

Explanation

`T=6s A=5cm`
`x=Asin(omegat+(pi)/(2))`
`therefore 2.5=5cosomegat`
`omegat=cos^(-1)(0.5)=(pi)/(3)`
`therefore (2pi)/(6)t=(pi)/(3) therefore t=1s`