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Two pendulum start oscillation in the sa...

Two pendulum start oscillation in the same direction at a same time from the same mean position time period are respectively `2 s` and `1.5s`. The phase difference between them, when the smaller pendulum is completed vibration, will be

A

`(pi)/(4)`

B

`(2pi)/(3)`

C

`(pi)/(2)`

D

`(3pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Deltaphi=omega_(2)t-omega_(1)t`
`=((2pi)/(T_(2))-(2pi)/(T_(1)))`
`=2pit((1)/(T_(2))-(1)/(T_(1)))`
`=2pixx1.5((1)/(1.5)-(1)/(2))=(pi)/(2)`
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