If the length of the seconds pendulum is increases by 4%, how many seconds it will lose per day?

Options

A. 3456 s
B. 864 s
C. 432 s
D. 1728 s

Answer

D

Explanation

`l_(2)=1.02l_(1)(T_(2))/(T_(1))=sqrt(1.02)`
`=(1+0.02)^(1//2)`
`(T_(2)-T_(1))/(T_(1))=0.01`
`T_(2)-T_(1)=0.02`
In one oscillation it looses 0.02
`therefore 43200.......? 0.04xx43200=1728s`