If acceleration due to gravity on the moon is one-sixth that on the earth, then the length and time period of seconds pendulum on the surface of moon are

Options

A. 6 m, 1.5 s
B. 1/6 m, 2 s
C. 1/6 m, 0.5 s
D. 6 m, 2 s

Answer

B

Explanation

`(l_(2))/(l_(1))=(g_(2))/(g_(1))=(1)/(6)`
`l_(2)=(1)/(6)m`
`T_(2)=2s`
Since, it is a seconds pendulum.