The bob of a simple pendulum of length L, is displaced through `90^(@)`, from its mean position and then released. What will be the tension in the string when the bob of mass m will be at its lowest position?

Options

A. mg
B. 3 mg
C. 2 mg
D. 6 mg

Answer

B

Explanation

`E=(1)/(2)mv^(2)`
`=(1)/(2)(m^(2)v^(2))/(m)=(p^(2))/(2m)`
`therefore p^(2)=2mE" " therefore p=sqrt(2mE)`.