If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

Options

A. `5 : 4`
B. `4 : 5`
C. `25 : 16`
D. `16 : 25`

Answer

C

Explanation

`n_(1)=(t)/(T_(1))`
`therefore t=n_(1)T_(1)`
`n_(1)T_(1)=n_(2)T_(2)`
`(T_(1))/(T_(2))=(n_(2))/(n_(1))=(25)/(20)=(5)/(4)`
As, `T_(1)propsqrt(l_(1))andT_(2)propsqrt(l_(2))`
`therefore (T_(1))/(T_(2))=sqrt((l_(1))/(l_(2)))`
`(5)/(4)=sqrt((l_(1))/(l_(2)))`
`(25)/(16)=(l_(1))/(l_(2))`