If length of seconds pendulum is increased by 0.3%, its new time period would be

Options

A. 2.0018 s
B. 2.0009 s
C. 2.06 s
D. 2.003 s

Answer

D

Explanation

`(DeltaT)/(T)=(1)/(2)(Deltal)/(l)=(1)/(2)xx(0.3)/(100)`
`DeltaT=(T)/(2)xx0.003=(2)/(2)xx0.003`
`DeltaT=0.003`
`T_(2)-T_(1)=0.003`
`T_(2)=T_(1)+0.003=2.003s`