A spring when stretched upto 2 cm has potential energy u. If it is stretched upto 10 cm, potential energy would be

Options

A. u/25
B. u/5
C. 5 u
D. 25 u

Answer

D

Explanation

`u_(1)=(1)/(2)kx_(1)^(2)andu_(2)=(1)/(2)kx_(2)^(2)`
`(u_(2))/(u_(1))=(x_(2)^(2))/(x_(1)^(2))thereforeu_(2)(uxx100)/(4)=25u`