1 kg weight is suspended to a weightless spring and it has time period T. If now 4 kg weight is suspended from the same spring the time period will be

Options

A. T
B. `T//2`
C. `2T`
D. 4T

Answer

C

Explanation

`T_(1)=2pisqrt((m)/(k))=2pisqrt((1)/(k))`
`T_(2)=2pisqrt((4)/(k))=2pixx2sqrt((1)/(k))`
`(T_(2))/(T_(1))=(2)/(1) therefore T_(2)=2T_(1)=2T`