Home
Class 12
PHYSICS
A block of mass 2 kg executes SHM on a s...

A block of mass 2 kg executes SHM on a smooth horizontal plane under the action of restoring force of a spring. If the amplitude and time period of oscillation are 0.05 m and `pi//5` second, the maximum force exerted by the spring on the block is

A

5 N

B

10 N

C

100 N

D

19.6 N

Text Solution

Verified by Experts

The correct Answer is:
B
`omega=(2pi)/(T)=(2pi)/(pi//5)`
`omega=10" rad/s"`
`F=momega^(2)A`
`=2xx10^(2)xx0.05`
`=10N`
Promotional Banner

Topper's Solved these Questions

  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise COMMUNICATION SYSTEMS|1 Videos

  • QUESTION PAPER - MH-CET 2018

    NIKITA PUBLICATION|Exercise MCQ|50 Videos

Similar Questions

Explore conceptually related problems

A block of mass 5 kg executes simple harmonic motion under the restoring force of a spring. The amplitude and the time period of the motion are 0.1 m and 3.14 s respectively. Fnd the maximum force exerted by the spring on the block.

A block of mass 2kg executes simple harmonic motion under the reading from at a spring .The angular and the time period of motion are 0.2 cm and 2pi sec respectively Find the maximum force execute by the spring in the block.

A block of mass 0.5 kg hanging from a vertical spring executes simple harmonic motion of amplitude 0.1 m and time period 0.314s. Find the maximum fore exerted by the spring on the blockl.

A bullted of mass m embeds itself in a block of mass M resting on a smooth horizontal surface, attached to a spring of force constant k. If the initial sped of the bullet is v_(0) along horizontal, find (a) the maximum compression of the spring and (b) the time forthe bullet - block system to come to rest.

A block is executing SHM on a rough on a horizontal surface under the action of an external variable force. The force is plotted against the position x of the particle from the mean position.

Two blocks rest on a smooth horizontal surface. They are connected by a spring of force constant k. If the system is set into oscillation find its time period.

A block of mass m moving with velocity v_(0) on a smooth horizontal surface hits the spring of constant k as shown. Two maximum compression in spring is

A block of mass m is suspended from a spring and executes vertical SHM of time period T as shown in Fig. The amplitude of the SHM is A and spring is never in compressed state during the oscillation. The magnitude of minimum force exerted by spring on the block is

A block of mass m is placed on a smooth inclined plane of inclination theta with the horizontal. The force exerted by the plane on the block has a magnitude

A block of mass 0.2 kg is attached to a mass less spring of force constant 80 N/m as shown in figure. Find the period of oscillation. Take g=10 m//s^(2) . Neglect friction

NIKITA PUBLICATION-OSCILLATIONS -MCQ
  1. A block of mass 0.5 kg hanging from a vertical spring executes simple ...

    Text Solution

    |

  2. A block of mass m hangs from a vertical spring of spring constant k. I...

    Text Solution

    |

  3. A block of mass 2 kg executes SHM on a smooth horizontal plane under t...

    Text Solution

    |

  4. A body of mass 10 kg is suspended by a massless coil spring of natural...

    Text Solution

    |

  5. A load of mass M is attached to the bottom of a spring of mass 'M //3'...

    Text Solution

    |

  6. The maximum velocity and the maximum acceleration of a body moving in ...

    Text Solution

    |

  7. A particle executes simple harmonic motion of ampliltude A. At what di...

    Text Solution

    |

  8. Two springs of constants k1 and k2 have equal maximum velocities, when...

    Text Solution

    |

  9. The force constant of a wire is k and that of another wire is . 2k Whe...

    Text Solution

    |

  10. If a simple pendulum oscillates with an amplitude of 50 mm and time pe...

    Text Solution

    |

  11. The time period of a bar magnet in uniform magnetic field vec(B) is 'T...

    Text Solution

    |

  12. W denotes to the total energy of a particle in linear S.H.M. At a poin...

    Text Solution

    |

  13. In S.H.M. path length is 4 cm and maximum accelertion is 2pi^(2) cm//s...

    Text Solution

    |

  14. Time period of pendulum is 6.28 s and amplitude of oscillation is 3 cm...

    Text Solution

    |

  15. The length of a pendulum is halved. Its energy will be

    Text Solution

    |

  16. Dimensions of force constant are

    Text Solution

    |

  17. The time period of oscillation of a particle that executes SHM is 1.2s...

    Text Solution

    |

  18. Particle moves from extreme position to mean position, its

    Text Solution

    |

  19. Spring is pulled down by 2 cm. What is amplitude of its motion?

    Text Solution

    |

  20. Simple pendulum is executing simple harmonic motion with time period T...

    Text Solution

    |