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Two springs of constants `k_1` and `k_2` have equal maximum velocities, when executing simple harmonic motion. The ratio of their amplitudes (masses are equal) will be

A

`(k_(1))/(k_(2))`

B

`(k_(2))/(k_(1))`

C

`((k_(1))/(k_(2)))^(1//2)`

D

`((k_(2))/(k_(1)))^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`v_(1)=v_(2)`
`A_(1)omega_(1)=A_(2)omega_(2)`
`(A_(1))/(A_(2))=(omega_(2))/(omega_(1))=(T_(1))/(T_(2))=sqrt((k_(2))/(k_(1)))`
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