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Simple pendulum is executing simple harm...

Simple pendulum is executing simple harmonic motion with time period `T`. If the length of the pendulum is increased by `21%`, then the increase in the time period of the pendulum of the increased length is:

A

0.22

B

0.2

C

0.33

D

0.44

Text Solution

Verified by Experts

The correct Answer is:
B

`(T_(2))/(T_(1))=sqrt((l_(2))/(l_(1)))=sqrt(1.44)=1.2`
`(T_(2)-T_(1))/(T_(1))=1.2-1=0.2=20%`.
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