The pendulum is acting as second pendulum on earth. Its time on a planet, whose mass and diameter are twice that of earth, is

Options

A. `sqrt(2) s`
B. `2 s`
C. `2 sqrt(2) s`
D. `1//sqrt(2)`

Answer

C

Explanation

`(T_(2))/(T_(1))=sqrt((g_(1))/(g_(2)))=sqrt((M_(1))/(M_(2))((R_(2))/(R_(1)))^(2))=sqrt((M_(1))/(2M_(1))xx4)`
`T_(2)=2sqrt(2)s`