The displacement of a particle performin...

The displacement of a particle performing simple harmonic motion is given by, `x=8" "sin" "omegat+6cos" "omegat`, where distance is in cm and time is in second. What is the amplitude of motion?

A

10 cm

B

14 cm

C

2 cm

D

3.5 cm

Text Solution

Verified by Experts

The correct Answer is:

A

`x=8sinomegat+6cosomegat`
`R=sqrt(A_(1)^(2)+A_(2)^(2))=sqrt(64+36)=sqrt(100)`
`=10m`.

Topper's Solved these Questions

MHT-CET 2016
NIKITA PUBLICATION|Exercise COMMUNICATION SYSTEMS|1 Videos
QUESTION PAPER - MH-CET 2018
NIKITA PUBLICATION|Exercise MCQ|50 Videos

Similar Questions

Explore conceptually related problems

The displacement of a particle in simple harmonic motion in one time period is

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :

The equation of a simple harmonic motion is given by x =6 sin 10 t + 8 cos 10 t , where x is in cm, and t is in seconds. Find the resultant amplitude.

The displacement of a particle executing simple harmonic motion is given by x=3sin(2pit+(pi)/(4)) where x is in metres and t is in seconds. The amplitude and maximum speed of the particle is

The epoch of a simple harmonic motion represented by x = sqrt(3)sin omegat + cos omega t m is

The displacement s of a particle at time t is given by s=alpha sin omegat+beta cos omegat then acceleration at time t is

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The displacement x of a particle in motion is given in terms of time by x(x-4) =1 -5 cos omegat

NIKITA PUBLICATION-OSCILLATIONS -MCQ

The pendulum is acting as second pendulum on earth. Its time on a plan...
Text Solution
|
A simple pendulum of length I and mass (bob) m is suspended vertically...
Text Solution
|
The displacement of a particle performing simple harmonic motion is gi...
Text Solution
|
If a bar magnet of magnetic moment M is kept in a uniform magnetic fie...
Text Solution
|
A particle of mass m is executing SHM about its mean position. The tot...
Text Solution
|
A load of mass 100 gm increases the length of wire by 10 cm. If the sy...
Text Solution
|
The acceleration due to gravity changes from 9.8 m//s^(2) to 9.5 m//s^...
Text Solution
|
Starting from the extreme position, the time taken by an ideal simple ...
Text Solution
|
A mass M is suspended from a spring of negiliglible mass the spring is...
Text Solution
|
In SHM, graph of which of the following is a straight line?
Text Solution
|
A magnet, when suspended in an external magnetic field, has a period o...
Text Solution
|
A body performing SHM about its mean position with period 24 s, after ...
Text Solution
|
In simple harmonic motion, the wrong statement is
Text Solution
|
Time period of pendulum on earth surface is T(1). Its time period at a...
Text Solution
|
A bar magnet is oscillating in a uniform magnetic field of induction 0...
Text Solution
|
The total work done by a restoring force in simple harmonic motion of ...
Text Solution
|
In simple harmonic motion, acceleration of the particle is zero, when ...
Text Solution
|
An amplitue of a simple pendulum of a period 'T' and length 'L' is inc...
Text Solution
|
The maximum velocity of a particle executing S.H.M. is u. If the ampli...
Text Solution
|
For a constant force the work done in stretching if spring constant k(...
Text Solution
|