A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant is

Options

A. `(pi^(2)mA^(2))/(T^(2))`
B. `(2pi^(2)mA^(2))/(T^(2))`
C. `(4pi^(2)mA^(2))/(T^(2))`
D. `(8pi^(2)mA^(2))/(T^(2))`

Answer

B

Explanation

`E=(1)/(2)momega^(2)A^(2)=(m4pi^(2)A^(2))/(T^(2))=(4pi^(2)mA^(2))/(T^(2))`