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A simple pendulm has a length L and a bo...

A simple pendulm has a length L and a bob of mass M. The bob is vibrating with amplitude a .What is the maximum tension in the string?

A

`T_("max")=mg[1+((A)/(l))^(2)]`

B

`T_("max")=mg[1-((A)/(l))^(2)]`

C

`T_("max")=mg[1-((l)/(A))^(2)]`

D

`T_("max")=mg[1+((l)/(A))^(2)]`

Text Solution

Verified by Experts

The correct Answer is:
A


`T=mgcostheta+(mv^(2))/(r)`
`v_(max)=Aomegaandcos=1`
`therefore T_(max)=mg+(mv_(max)^(2))/(r)`
`theta=(x)/(l)andr=l`
`T_(max)=mg+(mA^(2)omega^(2))/(l)=mg+(mA^(2)g)/(l^(2))`
`=mg[1+(A^(2))/(l^(2))]=mg[1+((A)/(l))^(2)]`
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