Home
Class 12
PHYSICS
Two particles perform linear simple harm...

Two particles perform linear simple harmonic motion along the same path of length 2 A and period T as shown in the graph below. The phase difference between them is

A

zero rad

B

`(pi)/(4)` rad

C

`(pi)/(2)` rad

D

`(3pi)/(4)` rad

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise COMMUNICATION SYSTEMS|1 Videos

  • QUESTION PAPER - MH-CET 2018

    NIKITA PUBLICATION|Exercise MCQ|50 Videos

Similar Questions

Explore conceptually related problems

Find the phase difference between two particles executing simple harmonic motion with the same frequency if they are found inn the states shown in the figures at four different points of time.

A particle executes a linear simple harmonic motion of amplitude 20 cm and time period 4 s. The minimum time period required for the particle to move between two points located at 10 cm on either side of equilibrium position is t seconds, then compute 3t + 2 .

Knowledge Check

  • Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is

    A
    `(11)/(6)pi`
    B
    `pi`
    C
    `(5)/(3)pi`
    D
    `(3)/(5)pi`

  • Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

    A
    Zero
    B
    `(pi)/(6)` radian
    C
    `(pi)/(4)` radian
    D
    `(pi)/(2)` radian

  • Two particles A and B execute simple harmonic motion of period T and 5T/4. The start from mean position. The phase difference between them when the particle A complete one oscillation will be

    A
    `pi//2`
    B
    zero
    C
    `2pi//5`
    D
    `pi//4`

    • Similar Questions

    Explore conceptually related problems

    Two particles A and B execute simple harmonic motions of period T and 5T//4 . They start from mean position. The phase difference between them when the particle A complete an oscillation will be

    A body is performing simple harmonic motion of amplitude A and time period T. The figure shown position-time graph of the body . At any time t, acceleration of the body is f, then which of the following graphs is/are appropriate?

    Two linear simple harmonic motions of equal amplitude and frequency are impressed on a particle along x and y axis respectively. The initial phase difference between them is pi/2 . The resultant path followed by the particle is

    The phase (at a time t) of a particle in simple harmonic motion tells

    A mass M is performing linear simple harmonic motion. Then correct graph for acceleration a and corresponding linear velocity v is

    Home
    Profile