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A particle executes S.H.M. of amplitude ...

A particle executes S.H.M. of amplitude 25 cm and time period 3 s. What is the minimum time required for the particle to move between two points 12.5 cm on either side of the mean position ?

A

0.6 s

B

0.5 s

C

0.4 s

D

0.2 s

Text Solution

Verified by Experts

The correct Answer is:
B
`t=(T)/(12)+(T)/(12)=(T)/(6)`
`=(3)/(6)=(1)/(2)=0.5s`
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