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A simple pendulum is oscillating with am...

A simple pendulum is oscillating with amplitue A and angular frequency `omega` At ratio of kinetic energy to potential energy is

A

`(x^(2))/(A^(2)-x^(2))`

B

`(x^(2)-A^(2))/(x^(2))`

C

`(A^(2)-x^(2))/(x^(2))`

D

`(A-x)/(x)`

Text Solution

Verified by Experts

The correct Answer is:
C

`(KE)/(PE)=((1)/(2)momega^(2)[A^(2)-x^(2)])/((1)/(2)momega^(2)x^(2))=(A^(2)-x^(2))/(x^(2))`
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