Two spring of force constants `K_(1) and K_(2) (K_(1)gtK_(2))` are stretched by same force. If `W_(1) and W_(2)` be the work done stretching the spring then……..

Options

A. `W_(1)=W_(2)`
B. `W_(1)ltW_(2)`
C. `W_(1)gtW_(2)`
D. `W_(1)=W_(2)=0`

Answer

B

Explanation

`W_(1)=fx_(1) because f=K_(1)x_(1)`
`W_(2)=fx_(2) because f=K_(2)x_(2)`
`(W_(1))/(W_(2))=(x_(1))/(x_(2))(K_(1))/(K_(2))=(x_(2))/(x_(1))`
`therefore (W_(1))/(W_(2))=(K_(2))/(K_(1))`
As `K_(1)gtK_(2)`
`(W_(1))/(W_(2))lt1`
`W_(1)leW_(2)`