Home
Class 12
PHYSICS
In a potentiometer experiment the balanc...

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of `10Omega` is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

A

`l_(1) =l_(2)((R+r)/(R))`

B

`l_(1) =l_(2)((R)/(R+r))`

C

`l_(1) =l_(2)((R)/(R-r))`

D

`l_(1) =l_(2)((R-r)/(R))`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MCQS FROM BOARD EXAM

    NIKITA PUBLICATION|Exercise MAGNETIC EFFECTS OF ELECTRIC CURRENT|4 Videos

  • MCQS FROM BOARD EXAM

    NIKITA PUBLICATION|Exercise ELECTROMAGNETIC INDUCTION|2 Videos

  • MCQS FROM BOARD EXAM

    NIKITA PUBLICATION|Exercise ELECTROSTATICS|5 Videos

  • MAGNETISM

    NIKITA PUBLICATION|Exercise MCQs|249 Videos

  • MH-CET - 2017

    NIKITA PUBLICATION|Exercise CUMMUNICATION SYSTEMS|1 Videos

Similar Questions

Explore conceptually related problems

In a potentiometer experiment, the balancing length with a cell is 560cm. When an external resistance of 10ohms is connected in parallel to the cell the balancing length changs by 60cm. The internal resistance of the cell in ohm is

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

The emf of cell is balanced by balancing length 450 cm . When the resistance of 10 Omega is connected across the cell, balancing length changes by 100 cm. The internal resistance of a cell is

In a potentiometer experiment , the balancing length for a cell was found to the 1.20 M . Now , a resistance of 10 Omega is connected across the terminals of this cell and the balancing length becomes 80 cm . The internal resistance of this cell is .

In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2Omega , the balancing length becomes 120 cm.The internal resistance of the cell is

In potentiometer experiment when terminates of the cell is at distance of 52 cm, then no current flows through it. When 5ohm shunt resistance is connected in it then balance length is at 40 cm. The internal resistance of the cell is

In a potentiometer arrangement for determining the emf of cell, the balance point of the cell in open circuit is 350 cm. When a resistance of 9 Omega is used in the external circuit of cell , the balance point shifts to 300 cm. Determine the internal resistance of the cell.

A 2.0V potentiometer is used to determine the internal resistance ofa I.SY cell. The balance point of the cell in the open circuit is obtained at 75cm. When· a resistor of 10Omega is connected across the cell, the balance point shifts to 60cm. The internal resistance of the cell is: