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The magnitude of electric field intensit...

The magnitude of electric field intensity E is such that, an electron placed in it would experience an electrical force equal to its weight is given by

A

`e//mg`

B

`mg//e`

C

mge

D

can not be found

Text Solution

Verified by Experts

The correct Answer is:
B
Force due to electric field = weight
qE = mg
`therefore" "E=(mg)/q=(mg)/e`
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