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Two capacitors each of 1muF capacitance ...

Two capacitors each of `1muF` capacitance are connected in parallel and are then charged by 200 V. The total energy of their charges is

A

0.01 J

B

0.02 J

C

0.04 J

D

0.06 J

Text Solution

Verified by Experts

The correct Answer is:
C
`E=E_(1)+E_(2)=1/2(C_(1)+C_(2))V^(2)`
`=1/2xx2xx10^(-6)xx4xx10^(4)`
= 0.04J
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