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A square wire loop with sides 0.5 m is p...

A square wire loop with sides 0.5 m is placed with its plane perpendicular to the magnetic field. The resistance of the loop is `5Omega`. The rate at which the magnetic induction should be changed so that a current of 0.1 A is induced in the loop is

A

4 T/s

B

3 T/s

C

2 T/s

D

1 T/s

Text Solution

Verified by Experts

The correct Answer is:
C

`e=(dphi)/(dt)`
`IR=(AdB)/(dt)`
`(dB)/(dt)=(IR)/(A)=(0.1xx5)/(0.25)=2T//s`
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