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A black rectangular surface of area A em...

A black rectangular surface of area A emits energy E per second at `27^circC`. If length and breadth are reduced to one third of initial value and temperature is raised to `327^circC`, then energy emitted per second becomes

A

`(4E)/(9)`

B

`(7E)/(9)`

C

`(10E)/(9)`

D

`(16E)/(9)`

Text Solution

Verified by Experts

The correct Answer is:
D
`T_(1)=27+273=300K,L_(2)=(1)/(3)L_(1)`
`T_(2)=273+32=600K`
`(E_(2))/(E_(1))=(A_(2))/(A_(1))((T_(2))/(T_(1)))^(4)`
`=(L_(2)b_(2))/(L_(1)b_(1))xx((600)/(300))^(4)`
`=(1)/(3)xx(1)/(3)=16`
`E_(2)=(16)/(9)E_(1)`.
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