Assuming the expression for the pressure exerted by the gas on the walls of the container, it can be shown that pressure is

Options

A. `[(1)/(3)]^(rd)` kinetic energy per unit volume of a gas
B. `[(2)/(3)]^(rd)` kinetic energy per unit volume of a gas
C. `[(3)/(4)]^(th)` kinetic energy per unit volume of a gas
D. `(3)/(2)xx` kinetic energy per unit volume of a gas

Answer

B

Explanation

`P=(1)/(3)pC^(2)=(1)/(3)(M)/(V)C^(2)=(2)/(3)xx((1)/(2)MC^(2))/(V)`
`=((2)/(3))^(rd)` kinetic energy per unit volume.