Home
Class 12
PHYSICS
Alternating current of peak value ((2)/(...

Alternating current of peak value `((2)/(pi))` ampere flows through the primary coil of the transformer. The coefficient of mutual inductance between primary and secondary coil is 1 henry. The peak e.m.f. induced in secondary coil is (Frequency of AC= 50 Hz)

A

100 V

B

200 V

C

300 V

D

400 V

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(0)=(2)/(pi)A,L=1H,e_(0)=?f=50Hz`
`e_(0)=omegaLI_(0)`
`2pifLI_(0)`
`=2xx3.14xx50xx(2)/(pi)xx1`
=200V.
Promotional Banner

Topper's Solved these Questions

  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise ELECTRONS AND PHOTONS|2 Videos

  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise ATOMS, MOLECULES AND NUCLEI|3 Videos

  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise MAGNETISM|2 Videos

  • MH-CET - 2017

    NIKITA PUBLICATION|Exercise CUMMUNICATION SYSTEMS|1 Videos

  • OSCILLATIONS

    NIKITA PUBLICATION|Exercise MCQ|493 Videos

Similar Questions

Explore conceptually related problems

A 50 Hz a.c. current of crest value 1A flows through the primary of a transformer. If the mutual inductance between the primary and secondary be 1.5 H , the crest voltage induced in secondary is-

In a transformer , the coefficient of mutual inductance between the primary and the secondary coil is 0.2 henry. When the current changes by 5 ampere//second in the primary, the induced e.m.f. in the secondary will be

A 50 Hz AC current of crest value 1 A flows through the primary of a transformer. If the mutual inductance between the promary and secondary be 0.5 H, the creast voltage induced in the secondary is

The co-efficient of mutual induction between primary and secondary coil is 2H . Calculate induced e.m.f. If current of 4 A is cut off in 2.5 xx 10^(-4) seconds.

The coefficient of mutual inductance between the primary and secondary of the coil is 5H .A current of 10 A is cut - off in 0.5 s . The induced emf is :

A 50 Hz ac current of crest value 2 A flows mutual inductance between the primary and secondary be 0.25 H, the crest voltage induced in the secondary is

The coefficient of mutual inductance of two coils is 10 mH. IF the current flowing in one coil is 4A then the induced e.m.f in the second coil will be