Home
Class 12
CHEMISTRY
KMnO(4) reacts with KI in acidic medium ...

`KMnO_(4)` reacts with KI in acidic medium gives

A

`KIO_(3)+MnO_(2)`

B

`I_(2)+MnSO_(4)`

C

`I_(2)+MnO_(4)^(2-)`

D

`KOI+MnO_(4)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
B

`2KMnO_(4)+8H_(2)SO_(4)+ 10KIto 2MnSO_(4) +6K_(2) SO_(4)+5I_(2) +8H_(2)O`
Promotional Banner

Topper's Solved these Questions

  • COMPOUNDS CONTAINING NITROGEN

    NIKITA PUBLICATION|Exercise MCQ|418 Videos
  • ELECTROCHEMISTRY

    NIKITA PUBLICATION|Exercise Questions From Competitive Exam|46 Videos

Similar Questions

Explore conceptually related problems

KMnO_(4) reacts with KI in basic medium to from I_(2) and MnO_(2) . When 250 mL of 0.1 M KI solution is mixed with 250 mL of 0.02 M KMnO_(4) in basic medium, what is the number of moles I_(2) formed ?

Equivalent weight of KMnO_(4) acting as an oxidant in acidic medium is

Determine the equivalent weight of the following oxidising and reducing agents : (a) KMnO_(4) (reacting in acidic medium MnO_(4)^(-)rarrMn^(2+) ) (b) KMnO_(4) (reacting in neutral medium MnO_(4)^(-)rarr MnO_(2) )

On reduction of KMnO_(4) by oxalic acid in acidic medium, the oxidation number of Mn. What is the magnitude of is change?

When 1 mole of KMnO_(4) is reacted with FeC_(2)O_(4) in acidic medium, then the reacted amount of FeC_(2)O_(4) is

KMnO_(4) oxidises I^(-) to I_(2) in acidic medium. The equivalent weight of KMnO_(4) is :