General valence shell electronic configuration of `f-`block elements is

Options

A. `(n-2) d ^(0-1), ns^(2) ,(n-1)f^(0-14)`
B. `(n-2) f ^(1-14),(n-1) ^(0-1) d, ns^(2)`
C. `(n-2)^(0-14)f, (n-1)d^(0), ns^(2)`
D. `(n-1) f ^(1-14), (n-1) d ^(1), ns^(2)`

Answer

B

Explanation

We know that, the outer most shell in has only two electrons in s-orbitals. The penultimate two electrons in s-orbitals. The penultimate shell (n-1) has 0 to 1 1 electrons in d-orbitals. The anti penultimate shell (n-2) has 1 to 14 electrons in f-orbitals.
Hence general electronic configuration of f-block elements is
`ns^(2), (n-2)f ^(1-14), nd^(0-1)`
where n=6 for lanthanides
n =7 for lanthanides.