Home
Class 10
MATHS
In squareABCD," side "BC||side AD. Diago...

In `squareABCD," side "BC||`side AD. Diagonal AC and diagonal BD intersects in point Q. If `AQ=(1)/(3)AC,`then show that `DQ=(1)/(2)BQ.`

Text Solution

Verified by Experts

The correct Answer is:
`thereforeDQ=(1)/(2)BQ.`
Promotional Banner

Topper's Solved these Questions

  • CHALLENGING QUESTIONS

    CHETAN PUBLICATION|Exercise Theorem of Pythagoras|7 Videos

  • CHALLENGING QUESTIONS

    CHETAN PUBLICATION|Exercise Circle|9 Videos

  • CHALLENGING QUESTIONS

    CHETAN PUBLICATION|Exercise Statistics|4 Videos

  • ARITHMETIC PROGRESSION

    CHETAN PUBLICATION|Exercise ASSIGENMENT -3|10 Videos

  • CIRCLE

    CHETAN PUBLICATION|Exercise Assignment - 3 (Solve any two of the following questions):|3 Videos

Similar Questions

Explore conceptually related problems

In squareABCD, "seg " AD||"seg " BC. Diagonal AC and diagonal BC intersect each other in point P. Then show that (AP)/(PD)=(PC)/(BP)

In trapezium ABCD , side AB||DC Diagonals AC and BD intersect in O . If AB=20,DC=6, OB=15 . Find OD.

Attempt any Two of the following: In squareABCD ,seg AB ||seg CD . Diagonal AC and BD intersect each other at point P . Prove : (A(DeltaABP))/(A(DeltaCPD))=(AB^(2))/(CD^(2))

In the adjoing figure, squareABCD is a square. DeltaBCE on side BC and DeltaACF on the diagonal AC are similar to each other. Then, show that A(DeltaBCE)=(1)/(2)A(DeltaACF)

ABCD is a rectangle whose diagonals AC and BD intersect at O. If angleOAB= 46^(@) , find angleOBC .

ABCD is trapezium with AB || DC. The diagonal AC and BD intersect at E . If Delta AED ~ Delta BEC . Prove that AD = BC .

squareABCD is a parallelogram . Side BC intersects circle at point P . Prove that DC = DP .

squareABCD is a trapezium in which AB|| DC and its diagonals intersect each other at points O . Show that AO : BO = CO : DO.

In a quadrilateral ABCD, it is given that AB |\|CD and the diagonals AC and BD are perpendicular to each other. Show that AD.BC >= AB. CD .