Home
Class 10
MATHS
Two triangles, DeltaABC" and "DeltaDBC, ...

Two triangles, `DeltaABC" and "DeltaDBC,` lie on the same side of the base BC. From a point P on BC, `PQ||AB" and "PR||BD`are drawn. They intersect AC at Q DC at R. Prove that QR||AD.

Text Solution

Verified by Experts

The correct Answer is:
`therefore" seg "QR||" seg "AD`
Promotional Banner

Topper's Solved these Questions

  • CHALLENGING QUESTIONS

    CHETAN PUBLICATION|Exercise Theorem of Pythagoras|7 Videos
  • CHALLENGING QUESTIONS

    CHETAN PUBLICATION|Exercise Circle|9 Videos
  • CHALLENGING QUESTIONS

    CHETAN PUBLICATION|Exercise Statistics|4 Videos
  • ARITHMETIC PROGRESSION

    CHETAN PUBLICATION|Exercise ASSIGENMENT -3|10 Videos
  • CIRCLE

    CHETAN PUBLICATION|Exercise Assignment - 3 (Solve any two of the following questions):|3 Videos

Similar Questions

Explore conceptually related problems

squareABCD is a parallelogram . Side BC intersects circle at point P . Prove that DC = DP .

In the adjoining figure , seg PQ || AB. Seg PR || seg BD. Prove that QR||AD.

Two triangles QPR and QSR, right angled at P and S respectively are drawn on the same base QR and on the same side of QR. If PR and SQ intersect at T, prove that PT xx TR= ST xx TQ .

D is the midpoint of the side BC of Delta ABC . If P and Q are points o AB and on AC such that DP bisects angle BDA and DQ bisects angle ADC , then prove that PQ || BC

The perpendicular from A on side BC at a Delta ABC intersects BC at D such that DB=3 CD. Prove that 2 AB^(2)=2AC^(2)+BC^(2)

squareABCD is a parallelogram. Point E is on side BC , line DE intersects Ray AB in point . T Prove that : DExxBE=CExxTE .

ABCD is trapezium with AB || DC. The diagonal AC and BD intersect at E . If Delta AED ~ Delta BEC . Prove that AD = BC .

ABCD is quadrilateral with AB parallel to DC. A line drawn parallel to AB meets AD at P and BC at Q. prove that (AP)/(PD) = (BQ)/(QC)

The perpendicular PS on the base QR of Delta PQR intersects QR at S, such that QS=3 SR. Prove that 2PQ^(2)=2PR^(2)+QR^(2) .

In Delta ABC, AD is the bisector of hat(A). AB = 20 cm, AC = 28 cm, BC = 12 cm Find DC.