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In DeltaABC, D is a point on BC such tha...

In `DeltaABC,` D is a point on BC such that `(BD)/(DC)=(AB)/(AC).` prove that AD is the bisector of `angleA.` (Hint :produce BA to E such that AE=AC. Join EC)

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`therefore"Ray AD" is the " bisector " of "angleBAC.
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