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In DeltaABC,angleACB=90^(@), seg CDbot...

In `DeltaABC,angleACB=90^(@),`
seg `CDbotsideAB,`
`DEbotsideCB,`
Show that : `CD^(2)xxAC=ADxxABxxDE`

Text Solution

Verified by Experts

The correct Answer is:
`thereforeCD^(2)xxAC=ADxxABxxDE`
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