When `10 ml` of propane (gas) is combusted completely, volume of `CO_(2)(g)` obtained in similar condition is

Options

A. (a)`10 ml`
B. (b)`20 ml`
C. (c )`30 ml`
D. (d)`40 ml`

Explanation

To determine the volume of carbon dioxide (CO₂) produced when 10 ml of propane (C₃H₈) is combusted completely, we can follow these steps:

### Step-by-Step Solution:

1. **Write the Balanced Chemical Equation for the Combustion of Propane:**
The combustion of propane can be represented by the following balanced equation:
\[ C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O \]
This equation indicates that 1 mole of propane produces 3 moles of carbon dioxide.

2. **Identify the Volume of Propane Given:**
We are given 10 ml of propane (C₃H₈).

3. **Convert the Volume of Propane to Moles:**
At standard temperature and pressure (STP), 1 mole of gas occupies 22,400 ml. Therefore, we can convert the volume of propane to moles using the formula:
\[ \text{Moles of } C_3H_8 = \frac{\text{Volume of } C_3H_8}{22,400 \text{ ml}} = \frac{10 \text{ ml}}{22,400 \text{ ml}} = \frac{10}{22,400} \text{ moles} \]

4. **Calculate the Moles of CO₂ Produced:**
According to the balanced equation, 1 mole of propane produces 3 moles of carbon dioxide. Therefore:
\[ \text{Moles of } CO_2 = 3 \times \text{Moles of } C_3H_8 = 3 \times \frac{10}{22,400} = \frac{30}{22,400} \text{ moles} \]

5. **Convert Moles of CO₂ to Volume:**
Now, we convert the moles of CO₂ back to volume using the same molar volume at STP:
\[ \text{Volume of } CO_2 = \text{Moles of } CO_2 \times 22,400 \text{ ml} = \frac{30}{22,400} \times 22,400 \text{ ml} = 30 \text{ ml} \]

6. **Final Answer:**
The volume of CO₂ produced when 10 ml of propane is combusted completely is **30 ml**.