Two elements `X` and `Y` have atomic weight of `14` and `16`. They from a series of compounds `A,B,C,D and E` in which the same amount of element `X,Y` is present in the ratio `1:2:3:4:5`. If the compound `A` has `28` parts by weight of `X` and `16` parts by weight of `Y`, then the compound of `C` will have `28` parts weight of `X` and

Options

A. (a)`32` parts by weight of `Y`
B. (b)`48` parts by weight of `Y`
C. (c )`64` parts by weight of `Y`
D. (d)`80` parts by weight of `Y`

Answer

To solve the problem, we need to analyze the information given about the compounds formed by elements X and Y. Let's break it down step by step.

### Step 1: Understanding the Ratios
We know that the compounds A, B, C, D, and E contain elements X and Y in a specific ratio. The amount of Y in these compounds is in the ratio of 1:2:3:4:5. This means that for each compound, if we denote the amount of Y in compound A as 1 part, then in compound B it will be 2 parts, in compound C it will be 3 parts, and so on.

### Step 2: Analyzing Compound A
In compound A, we are given that:
- The weight of X = 28 parts
- The weight of Y = 16 parts

### Step 3: Establishing the Ratio for Compound C
Since we know the ratio of Y in the compounds is 1:2:3:4:5, we can express the amount of Y in compound C based on the amount of Y in compound A.

Given that:
- In compound A, Y = 16 parts (which corresponds to the first part of the ratio, i.e., 1 part)
- In compound C, Y will correspond to 3 parts of the ratio.

### Step 4: Calculating the Weight of Y in Compound C
To find the weight of Y in compound C, we can set up a proportion based on the ratio:
- If 1 part (in A) corresponds to 16 parts of Y, then 3 parts (in C) will correspond to:

\[ Y_C = 16 \text{ parts} \times 3 = 48 \text{ parts} \]

### Conclusion
Thus, in compound C, if there are 28 parts of X, there will be 48 parts of Y.

**Final Answer: 48 parts by weight of Y in compound C.**

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