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A sample of calcuium carbonate (CaCO(3))...

A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%, C=12%, O=48%` If the law of constant proportions is true. Then the weight of calcium in `4 g` of a sample of calcium carbonate obtained from another source will be

A

(a)`0.016 g`

B

(b)`0.10 g`

C

(c )`1.6 g`

D

(d)`16 g`

Text Solution

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The correct Answer is:
C
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