There are two common oxides of sulphur, one of which contains `50% O_(2)` by weight, the other almost exactly `60%`. The weight of sulphur which combine with `1 g` of `O_(2)` (fixed) are in the ratio of

Options

A. (a)`1:1`
B. (b)`2:1`
C. (c )`2:3`
D. (d)`3:2`

Explanation

To solve the problem, we need to determine the weight of sulfur that combines with 1 g of O₂ in two different oxides of sulfur, which contain 50% and 60% O₂ by weight, respectively.

### Step-by-Step Solution:

1. **Identify the Composition of the First Oxide:**
- The first oxide contains 50% O₂ by weight.
- This means that in 100 g of the compound, there are 50 g of O₂ and 50 g of sulfur (S).

2. **Calculate the Weight of Sulfur that Combines with 1 g of O₂ in the First Oxide:**
- The ratio of sulfur to O₂ in the first oxide is 50 g S to 50 g O₂.
- Therefore, for 1 g of O₂, the weight of sulfur (S) can be calculated as:
\[ \text{Weight of S} = \frac{50 \text{ g S}}{50 \text{ g O₂}} \times 1 \text{ g O₂} = 1 \text{ g S} \]

3. **Identify the Composition of the Second Oxide:**
- The second oxide contains 60% O₂ by weight.
- This means that in 100 g of the compound, there are 60 g of O₂ and 40 g of sulfur (S).

4. **Calculate the Weight of Sulfur that Combines with 1 g of O₂ in the Second Oxide:**
- The ratio of sulfur to O₂ in the second oxide is 40 g S to 60 g O₂.
- Therefore, for 1 g of O₂, the weight of sulfur (S) can be calculated as:
\[ \text{Weight of S} = \frac{40 \text{ g S}}{60 \text{ g O₂}} \times 1 \text{ g O₂} = \frac{2}{3} \text{ g S} \]

5. **Determine the Ratio of Sulfur Weights:**
- Now we have the weights of sulfur that combine with 1 g of O₂:
- For the first oxide: 1 g S
- For the second oxide: \(\frac{2}{3}\) g S
- The ratio of the weights of sulfur from the first oxide to the second oxide is:
\[ \text{Ratio} = \frac{1 \text{ g S}}{\frac{2}{3} \text{ g S}} = 1 \times \frac{3}{2} = \frac{3}{2} \]

6. **Final Answer:**
- The weight of sulfur that combines with 1 g of O₂ in the two oxides is in the ratio of \(3:2\).