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The sulphate of a metal M contains 9.87%...

The sulphate of a metal `M` contains `9.87%` of `M`, This sulphate is isomorphous with `ZnSO_(4).7H_(2)O`. The atomic weight of `M` is

A

(a)`40.3`

B

(b)`36.3`

C

(c )`24.3`

D

(d)`11.3`

Text Solution

Verified by Experts

The correct Answer is:
C
As the given sulphate is isomorphous with `ZnSO_(4). 7H_(2)O` its formula would be `MSO_(4).7H_(2)O`.m is the atomic weight of `M`, molecular weight of `MSO_(4).7H_(2)O`
`=m+32+64+126=m+222`
Hence `%` of `M=m/(m+222)xx100=9.87` (given) or
`100m=9387m+222xx9.87` or `90.13m=222xx9.87`
or `m=(222xx9.87)/90.13=24.3`
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