The equivelent weight of an element is `4`. Its chloride has a `V.D 59.25`. Then the valency of the element is

Options

A. (a)`4`
B. (b)`3`
C. (c )`2`
D. (d)`1`

Explanation

To find the valency of the element based on the given equivalent weight and vapor density of its chloride, we can follow these steps:

### Step 1: Understand the relationship between vapor density and molecular mass
The vapor density (VD) of a compound is defined as the molecular mass of the compound divided by the molecular mass of hydrogen (H₂), which is 2 g/mol. Therefore, we can express the molecular mass (M) of the chloride as:
\[ \text{VD} = \frac{M_{\text{chloride}}}{2} \]
Given that the vapor density of the chloride is 59.25, we can calculate the molecular mass of the chloride:
\[ M_{\text{chloride}} = 2 \times \text{VD} = 2 \times 59.25 = 118.5 \text{ g/mol} \]

### Step 2: Determine the equivalent weight of the chloride
The equivalent weight of a compound is calculated using the formula:
\[ \text{Equivalent weight} = \frac{\text{Molecular weight}}{\text{Valency}} \]
We know the equivalent weight of the element is 4. The equivalent weight of the chloride can be calculated by adding the equivalent weight of the element to the equivalent weight of chlorine (Cl), which is approximately 35.5 g/mol:
\[ \text{Equivalent weight of chloride} = \text{Equivalent weight of element} + \text{Equivalent weight of Cl} \]
\[ = 4 + 35.5 = 39.5 \text{ g/mol} \]

### Step 3: Calculate the valency of the element
Using the equivalent weight of the chloride and its molecular weight, we can find the valency (n) of the element:
\[ \text{Valency} = \frac{\text{Molecular weight of chloride}}{\text{Equivalent weight of chloride}} \]
Substituting the values we have:
\[ \text{Valency} = \frac{118.5}{39.5} \]
Calculating this gives:
\[ \text{Valency} \approx 3 \]

### Conclusion
The valency of the element is 3.

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