Home
Class 11
CHEMISTRY
A compound (80 g) on analysis gave C=24 ...

A compound `(80 g)` on analysis gave `C=24 g, H=4 g, O=32 g`. Its empirical formula is

A

`C_(2)H_(2)O_(2)`

B

`C_(2)H_(2)O`

C

`CH_(2)O_(2)`

D

`CH_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
D
`C=24 g, H=4 g, O=32 g`,
So, Molecular formula `=C_(2)H_(4)O_(4)`
So, Empirical formula`=CH_(2)O`
(Simplest formula)
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    A2Z|Exercise Mole Concept, Empirical Formula And Molecular Formula|47 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    A2Z|Exercise Stoichiometry And Limiting Reagents|27 Videos

  • S BLOCK ELEMENTS ( GROUP 13 - 14)

    A2Z|Exercise Section D - Chapter End Test|29 Videos

  • SOME BASIC PRINCIPALS OF ORGANIC CHEMISTRY

    A2Z|Exercise Section D - Chapter End Test|60 Videos

Similar Questions

Explore conceptually related problems

A compound (60 gm) on analysis gave C=24gm H=4gm and O=31gm , its empirical formula is

An organic compound on analysis gave C=5.45% , H=9.1% by mass. Its empirical formula is:

60 g of a compound on analysis gave 24 g C, 4 g H and 32 g O. The empirical formula of the compound is

60 g of a compound on analy6sis produced 24 g C , 4g H , and 32 g O . The empirical formula of the compound is

60 g of oraganic compound on analysis gave following result C=24 g , H=4g and O=32g. The compound can be

An organic compound on analysis gave C=48 g,H=8g and N=56 g. Volume of 1.0 g of the compound was foud to be 200ml at NTP. Molecular formula of the compound is

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C=38.71%,H, 9.67% and O=51.62% . The empirical formula of the compound would be:

A2Z-SOME BASIC CONCEPTS OF CHEMISTRY-Section D - Chapter End Test
  1. A compound (80 g) on analysis gave C=24 g, H=4 g, O=32 g. Its empirica...

    Text Solution

    |

  2. The number of meutrons in a drop water (20 drops =1 mL) at 4^(@)C

    Text Solution

    |

  3. Assuming that petrol is octane (C(8)H(18)) and has density 0.8 g//ml, ...

    Text Solution

    |

  4. Weight of one atom an element is 6.44 xx 10^(-23) g. Calculate g atom ...

    Text Solution

    |

  5. A compound contains 3.2% of oxygen. The minimum mol. Wt. of the compou...

    Text Solution

    |

  6. Arrange the following in order of increasing mass (i) 3.0115xx10^(23...

    Text Solution

    |

  7. Calculate the number of oxalic acid molecules in 100 mL of 0.02 N oxal...

    Text Solution

    |

  8. Arrange the following in order of decreasing mass (i) 1 F atom (ii...

    Text Solution

    |

  9. The number of millimoles contained in 0.160 g of NaOH is

    Text Solution

    |

  10. Number of mole of 1 m^(3) gas at NTP are:

    Text Solution

    |

  11. 0.5 g of fuming sulphuric acid (H2SO4+SO3), called oleum, is diluted w...

    Text Solution

    |

  12. The minimum quantity of H(2)S needed to precipitate 64.5 g of Cu^(2+) ...

    Text Solution

    |

  13. 34 g of H(2)O(2) is present in 1120 ml of H(2)O solution. This solutio...

    Text Solution

    |

  14. 1.82 g of a metal required 32.5 mL of N-HCl to dissolve it what is the...

    Text Solution

    |

  15. What volume at STP of ammonia gas will be required to be passed into 3...

    Text Solution

    |

  16. How many grams of NaHSO(3) will be required to react with one litre of...

    Text Solution

    |

  17. A 5.0 mL of solution of H(2)O(2) liberates 0.508 g of iodine from acid...

    Text Solution

    |

  18. 1.5 litre of a solution of normality N and 2.5 litre of 2 M HCl are m...

    Text Solution

    |

  19. The volume of 0.25 MH(3)PO(3) required to neutralise 25 ml of 0.03 M C...

    Text Solution

    |

  20. A 0.1097 g sample of As(2)O(3) requried 26.10 mL of KMnO(4) solution f...

    Text Solution

    |

  21. Borax in water gives B(4)O(7)^(2-)+7H(2)O rarr 4H(3)BO(3)+2OH^(-) ...

    Text Solution

    |