Arrange the following in order of increasing masses.
i. 1 molecules of oxygen ii. 1 atom of nitrogen
iii. 1 mol of water iv. `1 xx 10^(-10)` of iron
a. ii, i, iii, iv b. i, ii, iv, iii
c. ii, i, iv, iii d. i, ii, iii, iv

Options

A. (a)IIlt Ilt IIIlt IV
B. (b)IVlt IIIlt IIlt I
C. (c )IIlt IIIlt Ilt IV
D. (d)IIIlt IVlt Ilt II

Answer

A

Explanation

(I) 1 molecule of oxygen
`:' 6xx10^(23)` molcule has mass `=32 g`
`:.` 1 molecule of `O_(2)` has mass `=32/(6xx10^(23))=5.3xx10^(-23) g`
(II) 1 atom of nitrogen
`:' 2xx6xx10^(23)` atoms of `N_(2)` has mass `=28 g`
`:.` 1 atom of `N_(2)` has mass `=28/(2xx6xx10^(23))=2.3xx10^(-23)g`
(III) `1xx10^(-10)` mlecular weight of oxygen
`g` atomic weight `=2xx10^(-10)=2xx10^(-10) g`
`1xx10^(-10)` atomic weight of copper
So, order of increasing masses `IIlt Ilt IIIlt IV`.