The number of moles of `BaCO_(3)` which contains 1.5 moles of oxygen atoms is

Options

A. (a)0.5
B. (b)1
C. (c )3
D. (d)`6.02xx10^(23)`

Explanation

To find the number of moles of BaCO₃ (barium carbonate) that contain 1.5 moles of oxygen atoms, we can follow these steps:

### Step 1: Determine the number of oxygen atoms in one molecule of BaCO₃
Barium carbonate (BaCO₃) consists of one barium (Ba) atom, one carbon (C) atom, and three oxygen (O) atoms. Therefore, each molecule of BaCO₃ contains 3 oxygen atoms.

### Step 2: Relate moles of oxygen to moles of BaCO₃
Since each mole of BaCO₃ contains 3 moles of oxygen atoms, we can set up the following relationship:

- 1 mole of BaCO₃ = 3 moles of O

### Step 3: Calculate the number of moles of BaCO₃ for 1.5 moles of oxygen
To find the number of moles of BaCO₃ that would contain 1.5 moles of oxygen atoms, we use the relationship established in Step 2:

\[ \text{Moles of BaCO₃} = \frac{\text{Moles of O}}{3} \]

Substituting the number of moles of oxygen (1.5 moles):

\[ \text{Moles of BaCO₃} = \frac{1.5 \text{ moles of O}}{3} = 0.5 \text{ moles of BaCO₃} \]

### Final Answer:
The number of moles of BaCO₃ that contains 1.5 moles of oxygen atoms is **0.5 moles**.

---