Equivalent weight of KMnO(4) acting as a...

Equivalent weight of `KMnO_(4)` acting as an oxidant in acidic medium is

The same as its molecular weight

(b)Half of its molecular weight

(c )One-third of its molecular weight

(d)One-fifth of its molecular weight

Text Solution

Verified by Experts

The correct Answer is:

`Eq. wt. =(Mol. Wt.)/5`

Topper's Solved these Questions

SOME BASIC CONCEPTS OF CHEMISTRY
A2Z|Exercise Significant Figures, Rounding Off And Dimentional Analysis|18 Videos
SOME BASIC CONCEPTS OF CHEMISTRY
A2Z|Exercise Section B - Assertion Reasoning|26 Videos
SOME BASIC CONCEPTS OF CHEMISTRY
A2Z|Exercise Mole Concepts In Solution|47 Videos
S BLOCK ELEMENTS ( GROUP 13 - 14)
A2Z|Exercise Section D - Chapter End Test|29 Videos
SOME BASIC PRINCIPALS OF ORGANIC CHEMISTRY
A2Z|Exercise Section D - Chapter End Test|60 Videos

Similar Questions

Explore conceptually related problems

The equivalent weight of KMnO_(4) in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is M//.. ( where M is mol.wt. of KMnO_(4) )

The equivalent weight of KMnO_4 in a redox reaction in a neutral medium is .

KMnO_(4) reacts with KI in acidic medium gives

A : Equivalent weight of KMnO_(4) in acidic medium is M/5 . R : In acidic medium 1 mol of MnO_(4)""^(-) gains 5 electron.

STATEMENT-1 KMnO_(4) acts as powerful oxidising agent in acids, alkaline and neutral medium. STATEMENT-2: Equivalent weight of KMnO_(4) in acidic medium in M/5 and in strongly alkaline medium in M/3. STATEMENT-3 : KMnO_(4) solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

A2Z-SOME BASIC CONCEPTS OF CHEMISTRY-Redox Titration And Stoichiometry In Various Types Of Reaction

In the neutralization of Na(2)S(2)O(3) using K(2)Cr(2)O(7) by idometry...
Text Solution
|
When N(2) is converted into NH(3), the equivalent weight of nitrogen w...
Text Solution
|
Equivalent weight of KMnO(4) acting as an oxidant in acidic medium is
Text Solution
|
In the reaction: Na(2)S(2)O(3)+4Cl(2)+5H(2)O rarr Na(2)SO(4)+H(2)SO(4)...
Text Solution
|
In the reaction 2CuSO(4)+4KI rarr 2Cu(2)I(2)+I(2)+2K(2)SO(4) the equ...
Text Solution
|
KMnO(4) react with oxalic acid according to the equation, 2MnO(4)^(-)+...
Text Solution
|
28 NO(3)^(-)+3As(2)S(3)+4H(2)O rarr 6AsO(4)^(3-)+28NO+9SO(4)^(2-)+H^(+...
Text Solution
|
In order to prepare one litre normal solution of KMnO(4), how many gra...
Text Solution
|
HNO(3) oxidies NH(4)^(+) ions to nitrogen and itself gets reduced to N...
Text Solution
|
What is the concentration of nitrate ions if equal volumes of 0.1 M Ag...
Text Solution
|
How many litres of Cl(2) at STP will be liberated by the oxidation of ...
Text Solution
|
A solution containing Na(2)CO(3) and NaOH requires 300 ml of 0.1 N HCl...
Text Solution
|
Which of the following cannot give iodometric titrations?
Text Solution
|
KMnO(4) reacts with ferrous ammonium sulphate according to the equatio...
Text Solution
|
Calculate the mass of BaCO(3) produced when excess CO(2) is bubbled th...
Text Solution
|
The number of moles of KMnO(4) required to oxidise 1 mol of Fe(C(2)O(4...
Text Solution
|
The ratio of amounts of H(2)S needed to precipitate all the metal ions...
Text Solution
|
100 ml of 0.1 N hypo decolourised iodine by the addition of x g of cry...
Text Solution
|
How many grams of caustic potash required to completely neutralise 12....
Text Solution
|
What should be the weight and moles of AgCl precipitate obtained on ad...
Text Solution
|