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The specific charge of a proton is 9.6 x...

The specific charge of a proton is `9.6 xx 10^7 C kg^-1`, then for and `alpha-"particles"` it will be.

A

`2.4 xx 10^7 C kg^-1`

B

`4.8 xx 10^7 C kg^-1`

C

`19.2 xx 10^7 C kg^-1`

D

`38.4 xx 10^7 C kg^-1`

Text Solution

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The correct Answer is:
To find the specific charge of an alpha particle, we can follow these steps: ### Step 1: Understand the specific charge of a proton The specific charge of a proton is given as \( \frac{E}{m} = 9.6 \times 10^7 \, \text{C kg}^{-1} \). ### Step 2: Identify the charge and mass of an alpha particle An alpha particle consists of 2 protons and 2 neutrons. Therefore: - **Charge of an alpha particle**: Since it has 2 protons, the charge is \( 2 \times e \) (where \( e \) is the elementary charge, approximately \( 1.6 \times 10^{-19} \, \text{C} \)). - **Mass of an alpha particle**: The mass of an alpha particle is approximately \( 4 \, m_p \) (where \( m_p \) is the mass of a proton). ### Step 3: Calculate the specific charge of the alpha particle The specific charge \( \frac{E}{m} \) for the alpha particle can be calculated using the formula: \[ \frac{E}{m} = \frac{2e}{4m_p} \] This simplifies to: \[ \frac{E}{m} = \frac{1}{2} \cdot \frac{e}{m_p} \] ### Step 4: Substitute the specific charge of a proton We know the specific charge of a proton \( \frac{e}{m_p} \) is \( 9.6 \times 10^7 \, \text{C kg}^{-1} \). Therefore: \[ \frac{E}{m} = \frac{1}{2} \cdot 9.6 \times 10^7 \, \text{C kg}^{-1} \] ### Step 5: Perform the calculation Calculating this gives: \[ \frac{E}{m} = 4.8 \times 10^7 \, \text{C kg}^{-1} \] ### Conclusion The specific charge of an alpha particle is \( 4.8 \times 10^7 \, \text{C kg}^{-1} \). ---

To find the specific charge of an alpha particle, we can follow these steps: ### Step 1: Understand the specific charge of a proton The specific charge of a proton is given as \( \frac{E}{m} = 9.6 \times 10^7 \, \text{C kg}^{-1} \). ### Step 2: Identify the charge and mass of an alpha particle An alpha particle consists of 2 protons and 2 neutrons. Therefore: - **Charge of an alpha particle**: Since it has 2 protons, the charge is \( 2 \times e \) (where \( e \) is the elementary charge, approximately \( 1.6 \times 10^{-19} \, \text{C} \)). ...
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Knowledge Check

  • The specific charge of photon is 9.6xx10^7 C kg^(-1) then for an alpha -particle it will be

    A
    `38.4xx10^7 " C kg"^(-1)`
    B
    `19.2xx10^7 " C kg"^(-1)`
    C
    `2.4xx10^7 " C kg"^(-1)`
    D
    `4.8xx10^7 " C kg"^(-1)`
  • The specific charge of a proton is 9.6xx10^(7)"C kg"^(-1) . The specific charge of an alpha particle will be

    A
    `9.6xx10^(7)"C kg"^(-1)`
    B
    `19.2xx10^(7)"C kg"^(-1)`
    C
    `4.8xx10^(7)"C kg"^(-1)`
    D
    `2.4xx10^(7)"C kg"^(-1)`
  • Electrons move at right angles to a magnetic field of 1.5xx10^(-2) Tesla with a speed of 6xx10^(7)m//s . If the specific charge of the electron is 1.7xx10^(11)C//kg . The radius of the circular path will be

    A
    `2.9cm`
    B
    `3.9cm`
    C
    `2.35cm`
    D
    `3 cm`
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