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If V(0) is the Volume of a given mass of...

If `V_(0)` is the Volume of a given mass of gas at `273K` at constant pressure, then according to Charles's law, the volume at `10^(@)C` will be:

A

`10V_(0)`

B

`(2)/(273)(V_(0)+10)`

C

`V_(0)+(10)/(273)`

D

`(283)/(273)V_(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`(V_(0))/(273)=(V_(2))/(283)implies V_(2)=(283)/(273)V_(0)`
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A2Z-STATES OF MATTER-Section D - Chapter End Test
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