At definite temperature the volume of a definite mass of gas is `10L` at `5 atm` pressure, at the same temperature if the pressure of the gas is decreased to `1 atm`, the volume of same gas becomes

Options

A. `50 L`
B. `2 L`
C. `5 L`
D. `0. 5 L`

Answer

A

Explanation

`p_(1)= 5 atm`
`v_(1)= 10L`
`p_(2)= 1 atm " " V_(2)=?`
`P_(1)V_(1)= p_(2)V_(2)`
or ` (P_(1))/(P_(2))=(V_(1))/(V_(2))`
`(5)/(1) = (V_(2))/(10)`
`V_(2) = 50 L`