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A 0.5 dm^(3) flask contains gas A and 1 ...

A `0.5 dm^(3)` flask contains gas `A` and `1 dm^(3)` flask contains gas `B` at the same temperature. If density of `A= 3g//dm^(3)` and that of `B= 1.5g //dm^(3)` and the molar mass of `A= 1//2` of `B`, the ratio of pressure excerted by gases is:

A

`(P_(A))/(P_(B))=2`

B

`(P_(A))/(P_(B))=1`

C

`(P_(A))/(P_(B))=4`

D

`(P_(A))/(P_(B))=3`

Text Solution

Verified by Experts

The correct Answer is:
C

`V_(A)= 0.5dm^(3)`
`V_(B)= 1dm^(3)`
`d_(A)= 3g//dm^(3)`
`d_(B)= 1.5g//dm^(3)`
`M_(A)=(1)/(2)M_(B)`
`P_(A)=(D_(A)RT)/(M_(A)), p_(B)(d_(B)RT)/(M_(B))`
`(P_(A))/(P_(B))=(d_(A))/(d_(B))xx(M_(B))/(M_(A))implies (3)/(1.5)xx2= 4`
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