At a temperature `T, K`, the pressure of `4.0 gm` argon in a bulb is `P`. The bulb is put in a bath having temperature higher by `50 K` than the first one `0.8` of argon gas had to be removed to maintain original pressure. The temperature `T` is

Options

A. `510 K`
B. `200 K`
C. `100 K`
D. `73 K`

Answer

B

Explanation

Here, `T_(1)= TK " " T_(2)= 50+T`
`w_(1)= 4g " " w_(2)= 4-0.8= 3.2g`
`P=V= "constant"`
Then from `PV=(w)/(M)RT`
`w_(1)T_(1)=w_(2)T_(2)`
`implies 4xxT= 3.2xxx(50+T)`
`T= 200K`